# How do you solve #log_25 n=3/2#?

##### 1 Answer

Nov 21, 2016

We know that if

#n = 25^(3/2)#

#n = (sqrt(25))^3#

#n = (5)^3#

#n = 125#

Hopefully this helps!

Nov 21, 2016

We know that if

#n = 25^(3/2)#

#n = (sqrt(25))^3#

#n = (5)^3#

#n = 125#

Hopefully this helps!

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