How do you solve #log_2x = 3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Binayaka C. May 9, 2018 #x=8# Explanation: Relation between logarithmic form and exponential form is #log _b N = x # if # b^x =N# # :. log_2 x=3 :. x = 2^3 or x =8 # [Ans] Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 5321 views around the world You can reuse this answer Creative Commons License