How do you solve #log (2x + 4) = log (3x -12)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan N. Mar 6, 2018 #x=16# Explanation: #log(2x+4) = log(3x-12)# Remember that: #loga=logb ->a=b# (Assuming the same base) Hence, in this example: #2x+4 = 3x-12# #3x-2x = 4+12# #x = 16# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2454 views around the world You can reuse this answer Creative Commons License