How do you solve log_2x+log_4x=log_2 5?

1 Answer
P dilip_k
Apr 9, 2016

log_2x+log_4x=log_2 5
=>log_2x+1/log_x4=log_2 5
=>log_2x+1/log_x2^2=log_2 5
=>log_2x+1/(2log_x2)=log_2 5
=>log_2x+1/2xxlog_2x=log_2 5
=>log_2x+log_2x^(1/2)=log_2 5
=>log_2(x*x^(1/2))=log_2 5
=>(x*x^(1/2))=5
=>(x^(3/2))=5
:. x=5^(2/3)

Related questions
See all questions in Logarithmic Models
Impact of this question
1430 views around the world
You can reuse this answer
Creative Commons License