Question

How do you solve `log_3 (2x-1) = 3`?

Answer 1

`x=14`

Explanation:

To undo a logarithm with base `3`, exponentiate both sides with a base of `3`.

`3^(log_3(2x-1))=3^3`

`2x-1=27`

`2x=28`

`x=14`