# How do you solve #log_3 32 = x#?

##### 1 Answer

Nov 27, 2015

This is already 'solved' in that

but you can use the change of base formula to find:

#x = log(32)/log(3) = ln(32)/ln(3) ~~ 3.15465#

#### Explanation:

The change of base formula tells use that if

#log_a b = (log_c b)/(log_c a)#

This allows us to express

#log_3 32 = log(32)/log(3) = ln(32)/ln(3) ~~ 3.15465#