# How do you solve log_3 75 = 2x?

${\log}_{3} 75 = 2 x \implies {3}^{2 x} = 75 \implies {9}^{x} = 75 \implies x \log 9 = \log 75$
$\implies x = \log \frac{75}{\log {3}^{2}} = \log \frac{75}{2 \log 3}$