How do you solve \log _ { 3} ( \frac { 1} { 9} ) = x?

2 Answers

here x=-2

Explanation:

log_3(1/9)=x can be written aslog_3(9^-1)=xrArrlog_3(3^-2)=xrArr-2(log_3(3))=x
rArrx=-2 the properties I used are :
log(1/x)=-logx,log_aa=1,log_aa^2=2log_aa

Dec 8, 2017

x=-2

Explanation:

"using the "color(blue)"law of logarithms"

•color(white)(x)log_bx=nhArrx=b^n

log_3(1/9)=x

rArr1/9=3^x

"note that "1/9=3^-2=3^x

rArrx=-2