# How do you solve log_3 root4(5)<=x?

Jan 7, 2017

$x \ge 0.366$

#### Explanation:

${\log}_{3} \sqrt[4]{5} \le x$ can be written as

$x \ge {\log}_{3} \sqrt[4]{5}$

or $x \ge {\log}_{3} {\left(5\right)}^{\frac{1}{4}}$

or $x \ge \frac{1}{4} {\log}_{3} 5$

or $x \ge \frac{1}{4} \log \frac{5}{\log} 3$

or $x \ge \frac{1}{4} \times \frac{0.6990}{0.4771}$

or $x \ge \frac{1}{4} \times 1.465$

or $x \ge 0.366$