How do you solve ${log}_{3} x = 9 {log}_{x} 3$ $log_3 x = 9 log_x 3$ ?

Question

How do you solve ${log}_{3} x = 9 {log}_{x} 3$ $log_3 x = 9 log_x 3$ ?

1 Answer

Impact of this question

7409 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-18T23:55:48

Using the change of base rule you get

$\frac{log x}{log 3} = 9 \frac{log 3}{log x} \Rightarrow {(log x)}^{2} = {(3 log 3)}^{2} \Rightarrow (log x - 3 log 3) \cdot (log x + 3 log 3) = 0 \Rightarrow x = 3^{3} = 27 or x = \frac{1}{27}$ $logx/log3=9log3/logx=>(logx)^2=(3log3)^2=> (logx-3log3)*(logx+3log3)=0=> x=3^3=27 or x=1/27$

Science

Math

Humanities

... and beyond

How do you solve ${log}_{3} x = 9 {log}_{x} 3$ $log_3 x = 9 log_x 3$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve log3x=9logx3log_3 x = 9 log_x 3?

1 Answer

Related questions

Impact of this question

How do you solve ${log}_{3} x = 9 {log}_{x} 3$ $log_3 x = 9 log_x 3$ ?