How do you solve ${log}_{4} (1 - x) = 1$ $log_4(1-x)=1$ ?

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How do you solve ${log}_{4} (1 - x) = 1$ $log_4(1-x)=1$ ?

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Answer 1 · 2015-07-22T21:40:34

I found: $x = - 3$ $x=-3$

Explanation:

Use the definition of log as:
${log}_{a} x = b \to x = a^{b}$ $log_ax=b ->x=a^b$
to get:
$1 - x = 4^{1}$ $1-x=4^1$
$x = 1 - 4$ $x=1-4$
$x = - 3$ $x=-3$

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How do you solve ${log}_{4} (1 - x) = 1$ $log_4(1-x)=1$ ?

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How do you solve log4(1−x)=1log_4(1-x)=1?

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How do you solve ${log}_{4} (1 - x) = 1$ $log_4(1-x)=1$ ?