How do you solve log (4p-2)=log(-5p+5)?

Apr 5, 2018

$\textcolor{b l u e}{\frac{7}{9}}$

Explanation:

If:

$\log \left(4 p - 2\right) = \log \left(- 5 p + 5\right) \implies 4 p - 2 = - 5 p + 5$

$4 p - 2 = - 5 p + 5$

$9 p = 7$

$p = \frac{7}{9}$

Check:

$\log \left(4 \left(\frac{7}{9}\right) - 2\right) = \log \left(- 5 \left(\frac{7}{9}\right) + 5\right)$

$\log \left(\frac{10}{9}\right) = \log \left(\frac{10}{9}\right)$