How do you solve \log (4x+1)-\log (x-3)=1?

1 Answer
Feb 26, 2017

Use the property log_an - log_am = log_a(n/m).

log( (4x + 1)/(x - 3) )= 1

Recall that logx generally signifies a logarithm in base 10.

(4x + 1)/(x - 3) = 10^1

4x + 1 = 10(x - 3)

4x + 1 = 10x - 30

31= 6x

x = 31/6

Verify to make sure this is not an extraneous solution.

Hopefully this helps!