How do you solve \log (4x+1)-\log (x-3)=1?
1 Answer
Feb 26, 2017
Use the property
log( (4x + 1)/(x - 3) )= 1
Recall that
(4x + 1)/(x - 3) = 10^1
4x + 1 = 10(x - 3)
4x + 1 = 10x - 30
31= 6x
x = 31/6
Verify to make sure this is not an extraneous solution.
Hopefully this helps!