How do you solve #log_5 (x+3)= 3 + log_5 (x-3) #? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Shwetank Mauria Apr 10, 2016 Answer: #x=189/62=3 3/62# Explanation: As #log_ba=loga/logb# #log_5(x+3)=3+log_5(x-3)# can be written as #log(x+3)/log5=3+log(x-3)/log5# As #log5!=0#, multiplying both sides by #log5# #log(x+3)=3log5+log(x-3)# or #(x+3)=5^3(x-3)=125(x-3)# or #x+3=125x-375# or #124x=378# and #x=378/124=189/62=3 3/62# Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 146 views around the world You can reuse this answer Creative Commons License