How do you solve ${log}_{5} x + {log}_{5} 6 = 2$ $log_5 x + log_5 6 = 2$ ?

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Answer 1 · 2015-11-27T02:17:26

$x = \frac{25}{6}$ $x=25/6$

Know that: ${log}_{a} b + {log}_{a} c = {log}_{a} b c$ $log_ab+log_ac=log_abc$ .

${log}_{5} x + {log}_{5} 6 = 2$ $log_5x+log_5 6=2$

${log}_{5} 6 x = 2$ $log_5 6x=2$

$5^{2} = 6 x$ $5^2=6x$

$x = \frac{25}{6}$ $x=25/6$

How do you solve log5x+log56=2log_5 x + log_5 6 = 2?