# How do you solve log (5+x) - log (x-2) = log 2?

$x = 9$

#### Explanation:

Given equation:

$\log \left(5 + x\right) - \setminus \log \left(x - 2\right) = \setminus \log 2 \setminus \quad \left(\setminus \forall \setminus \setminus x > 2\right)$

$\setminus \log \left(\frac{5 + x}{x - 2}\right) = \setminus \log 2$

Comparing the numbers on both the sides, we get

$\frac{5 + x}{x - 2} = 2$

$5 + x = 2 x - 4$

$x = 5 + 4$

$x = 9$