How do you solve #\log _ { 6} n = \frac { 1} { 2} \log _ { 6} 64#?
1 Answer
Apr 3, 2017
Explanation:
Use the following laws of logarithms to solve:
#•alnn = lnn^a#
We have:
#log_6 n = log_6 64^(1/2)#
#log_6 n = log_6 8#
It follows that
Hopefully this helps!
