How do you solve log_7(-2b+10)=log_7(3b)?

1 Answer

b=2

Explanation:

The solution

log_7 (-2b+10)=log_7 (3b)

Take the anti-logarithm of both sides of the equation

7^(log_7 (-2b+10))=7^(log_7 (3b))

-2b+10=3b

Solving for b

3b+2b=10

5b=10

(5b)/5=10/5

b=2

God bless....I hope the explanation is useful.