Question

How do you solve `log_7 x=log_2 9`?

Answer 1

Ok...I tried various things but the only thing I found is to change base of the second log and use a calculator to evaluate it as:
`log_7(x)=ln9/ln2=3.17` (where `ln` is the natural log).
so using the definition of logarithm:
`x=7^3.17=477.5`

Probably there are more elgant ways but...