How do you solve log_8 (1) + log_9 (9) + log_5 (25) + 3x= 6?

2 Answers
Jan 27, 2016

I found x=1

Explanation:

Here we can take advantage of the definition of log:
log_ax=y -> x=a^y
so that we get:
0+1+2+3x=6
3x=3
and
x=1

Remember that:
8^0=1
9^1=9
5^2=25

Jan 27, 2016

x= 1

Explanation:

To solve this problem, we need to remember severals logarithmic properties.

log_a a = 1 , given a is any positive number, a>0
log_a 1= 0
log_a a^n = n

We have

log_8 (1) + log_9(9) + log5(25) + 3x = 6

0 + 1 + log_5(5^2) + 3x =6
0 + 1 + 2 + 3x = 6
Combine like terms

3 + 3x = 6

3x = 3

x = 1