How do you solve $log_b(2)=0.24$ ?

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Answer 1 · 2016-06-22T09:07:10

$b =17.9594$

$log_b(2)=0.24->2=b^{0.24}$

Applying $log_e$ to both sides

$log_e 2=0.24 log_e b$

then

$log_e b = log_e 2/0.24 = 2.88811$

Finally

$b = e^2.88811=17.9594$

How do you solve log_b(2)=0.24log_b(2)=0.24?