Question

How do you solve `Log_b 64 = 6`?

Answer 1

`b^6=64->b^6 = 2^6->(b^6)^(1/6) = (2^6)^(1/6) ->b = 2` Or
`b^6=64->root6(b^6) =root6(64)->b=2`

Explanation:

First, use definition of logarithm to change to exponential form then solve for b by taking the sixth root of both sides.