# How do you solve log_b64=3?

Nov 10, 2016

Logarithms can be converted to exponential form using ${\log}_{a} \left(b\right) = n \to {a}^{n} = b$. So,for this problem, we have:

${b}^{3} = 64$

Equating exponents:

${b}^{3} = {4}^{3}$

$b = 4$

Hopefully this helps!