Question

How do you solve `log_d 12 = 6`?

Answer 1

`(12)^(1/6)=d`

Explanation:

To undo a logarithm, raise both sides to the power of the base of the logarithm.

`log_d12=6`

`d^(log_d12)=d^6`

`12=d^6`

`(12)^(1/6)=(d^6)^(1/6)`

`(12)^(1/6)=d`