Question

How do you solve `Log(x)= -0.123`?

Answer 1

`x=10^(=0.123)=0.7534`, nearly.

Explanation:

For logarithm, with any base b,

if `c=log_b a`,

then the inverse relation is

`a=b^c`

For common logarithms, b =10 and b is in hiding..

So, here, `x=10^(-0.123)=0.7534`, nearly.