Question

How do you solve `log (x-1)^2 = log (-5x-1)`?

Answer 1

`x = -1` or `x = -2`

Explanation:

`log (x-1)^2 = log (-5x-1)`
`x^2-2x+1 = -5x-1`
`x^2+3x+2 = 0`
`(x+1)(x+2) = 0`
`x = -1` or `x = -2`