How do you solve $log x = - 2$ $log x=-2$ ?

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Answer 1 · 2015-12-27T14:24:55

You apply the exponential function on both sides of the equality.

You apply exp, so $ln (x) = - 2 \Leftrightarrow x = e^{- 2} = \frac{1}{e^{2}}$ $ln(x) = -2 iff x = e^(-2) = 1/e^2$ .

How do you solve logx=−2log x=-2?