Question

How do you solve `log x^2+1=5`?

Answer 1

`x=100`

Explanation:

`log x^2 +1 =5`
`logx^2=4`-> subtract 1 from both sides
`2logx=4`->Use property `log_bx^n=n*log_b x`
`log x=2`-> divide both sides by 2
`10^2=x`->use property `y=log_bx iff b^y=x`
`x=100`