How do you solve $log x^2 + log 25 = 2$ ?

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Answer 1 · 2015-09-11T02:13:44

The answer is $x=2$

We have that

$logx^2+log25=2=>log25x^2=log100=>25x^2=100=>x^2=4=>x=2,x=-2$

But $x>0$ hence $x=2$

How do you solve log x^2 + log 25 = 2log x^2 + log 25 = 2?