How do you solve ${log x}^{2} = {(log x)}^{2}$ $log x^2 = (log x)^2$ ?

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Answer 1 · 2015-12-01T18:54:36

$1 or e^{2}$ $1 or e^2$

$y = log x$ $y = log x$

$2 y = y^{2}$ $2y = y^2$

$y = 0 or y = 2$ $y = 0 or y = 2$

$log x = 0 or log x = 2$ $log x = 0 or log x = 2$

$x = e^{0} or x = e^{2}$ $x = e^0 or x = e^2$

How do you solve logx2=(logx)2 log x^2 = (log x)^2?