How do you solve $log x = - 3$ $log x = -3$ ?

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Answer 1 · 2016-04-21T19:07:57

$x = \frac{1}{1000}$ $x=1/1000$

Use the Property: $y = {log}_{b} x \Leftrightarrow b^{y} = x$ $y=log_bx iff b^y=x$

$10^{- 3} = x$ $10^-3=x$

$x = \frac{1}{10^{3}}$ $x=1/10^3$

$x = \frac{1}{1000}$ $x=1/1000$

How do you solve logx=−3log x = -3?