Question

How do you solve `log(x+3)+log(x)=1`?

Answer 1

`log_10(x+3)+log_10(x)=1->log_10((x+3)(x))=1->log_10x^2+3x=1->10^1=x^2+3x`
`0=x^2+3x-10->0=(x+5)(x-2)->x=-5,x=2`

Explanation:

Use the property of logarithm for log of a product is the sum of the logs to change the sum to a product. Then use the definition to change from logarithmic form to exponential form then solve for x.