**Step 1)** Add #color(red)(10)# to each side of the inequality to isolate the #j# term while keeping the inequality balanced:

#3/4j - 10 + color(red)(10) >= 5 + color(red)(10)#

#3/4j - 0 >= 15#

#3/4j >= 15#

**Step 2)** Multiply each side of the inequality by #color(red)(4)/color(blue)(3)# to solve for #j# while keeping the inequality balanced:

#color(red)(4)/color(blue)(3) xx 3/4j >= color(red)(4)/color(blue)(3) xx 15#

#cancel(color(red)(4))/cancel(color(blue)(3)) xx color(blue)(cancel(color(black)(3)))/color(red)(cancel(color(black)(4)))j >= color(red)(4)/cancel(color(blue)(3)) xx color(blue)(cancel(color(black)(15)))5#

#j >= 20#

We can graph this solution as:

graph{x >= 20 [-30, 30, -10, 10]}