How do you solve $log (x - 5) = 2$ $Log(x-5)=2$ ?

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Answer 1 · 2015-09-11T02:11:10

The answer is $x = 105$ $x=105$

We have that

$log (x - 5) = 2 \Rightarrow (x - 5) = 10^{2} \Rightarrow x = 105$ $log(x-5)=2=>(x-5)=10^2=>x=105$

How do you solve log(x−5)=2Log(x-5)=2?