How do you solve $log (x + 7) = 1$ $log (x+7)=1$ ?

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Answer 1 · 2018-05-09T14:35:13

I tried this:

It depends upon the 'base" of your log. Let us say that is $10$ $10$ ; we can write:

${log}_{10} (x + 7) = 1$ $log_(10)(x+7)=1$

using the definition of log we can write:

$x + 7 = 10^{1}$ $x+7=10^1$

and:

$x = 10 - 7 = 3$ $x=10-7=3$

if you have a different base use the one you got instead of $10$ $10$ .

How do you solve log (x+7)=1log(x+7)=1 log (x+7)=1?