Question

How do you solve `log x+log 20=2`?

Answer 1

`x=5`

Explanation:

`log(x)+log(20) = log(20x)`

So, if `log(x)+log(20)=2`
then
`color(white)("XXX")log(20x)=2`

`rArrcolor(white)("XX")10^(log(20x)) = 10^2`

`rArrcolor(white)("XX")20x = 100`

`rArrcolor(white)("XX")x=5`