How do you solve #log x + log 5 = 2#?

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Answer 1 · 2016-06-12T13:34:58

#5x = 100 " " rArr x = 20#

Remember that with log questions, you can't work with log terms and number terms. Change them either all to log terms, or all to number terms.

#logx + log 5 = 2# should rather be written as:

#logx + log5 = log 100 " "log_10 100 =2 #

Now apply the log law to get the log of a single term:
#log x xx 5 = log 100#

#log 5x = log 100#

Because we have one log term on each side we can drop the logs and end up with

#5x = 100 " " rArr x = 20#