How do you solve #log5m = log5125#?

1 Answer
Apr 2, 2018

See explanation.

Explanation:

First we have to clarify what the equation is.

  • If the digit #5# on both sides is the base then the equation should be written as:

#log_5 m=log_5 125#

The bases are equal, so you can change the #log# equation into the equation of expressions under #log# signs:

#m=125#

  • However if the digit #5# is the part of number under the #log# sign we have:

#log5m=log5125#

If a base is not specified then it is equal to #10# and again as in the first case the bases are equal and #log# signs can be skipped:

#5m=5125#

After dividing both sides by #5# we get:

#m=1025#