# How do you solve  n^2 + 3n - 12 = 6?

Apr 29, 2018

$n = - 6 , 3$

#### Explanation:

Given: ${n}^{2} + 3 n - 12 = 6$.

Subtract $6$ from both sides.

${n}^{2} + 3 n - 12 - 6 = \textcolor{red}{\cancel{\textcolor{b l a c k}{6}}} - \textcolor{red}{\cancel{\textcolor{b l a c k}{6}}}$

${n}^{2} + 3 n - 18 = 0$

$\implies \left(n + 6\right) \left(n - 3\right) = 0$

$\therefore n = - 6 , 3$