# How do you solve n^2 + n - 12 = 0?

Apr 17, 2016

3 and -4

#### Explanation:

$y = {n}^{2} + n - 12 = 0$
Find 2 real roots, knowing sum (-b = -1) and product (c = -12).
They have opposite signs.
Factor pairs of (c - -12) --> (3, -4). This sum is -1 = -b. The 2 real roots are: 3 and - 4.