How do you solve #n+ 2n + 8+ 16= 0#?

Question

1253 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-23T23:06:41

See the entire solution process below:

Step 1) Combine the common terms on the left side of the equation:

#1n + 2n +24 = 0#

#(1 + 2)n + 24 = 0#

#3n + 24 = 0#

Step 2) Subtract #color(red)(24)# from each side of the equation to isolate the #n# term while keeping the equation balanced:

#3n + 24 - color(red)(24) = 0 - color(red)(24)#

#3n + 0 = -24#

#3n = -24#

Step 3) Divide each side of the equation by #color(red)(3)# to solve for #n# while keeping the equation balanced:

#(3n)/color(red)(3) = -24/color(red)(3)#

#(color(red)(cancel(color(black)(3)))n)/cancel(color(red)(3)) = -8#

#n = -8#