How do you solve $n/3-5=12$ ?

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Answer 1 · 2018-04-03T17:53:54

$n=51$

Isolate $n$

$n/3-5=12$

$n/3-5+5=12+5 rarr$ Add 5 to each side

$n/3=17 rarr$ Multiply each side by 3

$n/3*3=17*3$

$n=51 rarr$ This is the answer

Answer 2 · 2018-04-03T18:01:04

$n=51$

$n/3 -5 = 12$

$n/3 -5 +5 =12 +5$

$n/3 =17$

$n/3 xx3 =17 xx3$

$n=51$

How do you solve n/3-5=12n/3-5=12?