How do you solve #n/4 - 3 =4#?

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Answer 1 · 2018-03-26T22:46:39

The solution is #n=28#.

First, add #3# to both sides. Then, multiply by #4#. Here's what that process looks like:

#n/4-3=4#

#n/4-3color(blue)+color(blue)3=4color(blue)+color(blue)3#

#n/4color(red)cancelcolor(black)(-color(black)3color(blue)+color(blue)3)=4color(blue)+color(blue)3#

#n/4=4color(blue)+color(blue)3#

#n/4=7#

#n/4color(blue)(*4)=7color(blue)(*4)#

#n/color(red)cancelcolor(black)4color(blue)(*color(red)cancelcolor(blue)4)=7color(blue)(*4)#

#n=7color(blue)(*4)#

#n=28#

This is the answer. Hope this helped!