# How do you solve r-6r^2=-1?

Aug 8, 2015

$r = - \frac{1}{3}$ and $r = \frac{1}{2}$

#### Explanation:

$- 6 {r}^{2} + r + 1 = 0$ Add $1$ to both sides

$\left(- 3 r - 1\right) \left(2 r - 1\right) = 0$ Factor

$- 3 r - 1 = 0$

$- 3 r = 1$ so $r = - \frac{1}{3}$

$2 r - 1 = 0$

$2 r = 1$ so $r = \frac{1}{2}$