How do you solve rational equations #4/(t+2)= - 4/(3t+6) + 8#?

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Answer 1 · 2018-04-02T12:30:39

#t= -4/3#

Multiply both sides by #(t +2)(3t +6)# to get rid of the fractions

#4(3t +6) = -4(t +2) +8(t +2)(3t +6)#

#12t +24 = -4t -8 +8(3t^2 +12t +12)#

#12t +24 = -4t -8 +24t^2 +96t +96#

#24t^2 +80t +64 = 0#

#3t^2 +10t +8 = 0#

#(3t +4)(t +2) = 0#

#t= -2 or -4/3#

If you substitute these values into the original question then the answer is #t=-4/3#