# How do you solve rational equations [6 / (x-1)] = [4 / (x+1)]?

Mar 6, 2016

$x = - 5$
$\frac{\cancel{6}}{x - 1} = \frac{\cancel{4}}{x + 1}$
$\frac{3}{x - 1} = \frac{2}{x + 1}$
$3 \left(x + 1\right) = 2 \left(x - 1\right)$
$3 x + 3 = 2 x - 2$
$3 x - 2 x = - 2 - 3$
$x = - 5$