How do you solve #s+b=28# and #16s+19b=478#?
There are several ways to solve this type of problem. I think the substitution method to be a good choice for this particular problem.
Rewrite the first equation as:
Distribute the 16:
Subtract 448 from both sides:
Combine like terms:
Divide both sides by 3
Substitute 10 for b into the first equation:
See the entire solution process below:
Step 1) Solve the first equation for
Step 2) Substitute
Step 3) Substitute
The solution is: