How do you solve #sec^2x+0.5tanx=1# and find all solutions in the interval #[0,2pi)#?
1 Answer
Jul 10, 2016
Explanation:
Call tan x = t. Apply the trig identity:
The equation is transformed to:
t^2 + t/2 = 0
t(t + 1/2) = 0
There are 2 cases:
a. t = tan x = 0 --> arc x = 0 and arc x = pi
Calculator gives:
b. tan x = -1/2 --> arc
The co-terminal arc of
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