Question

How do you solve `sin^2(x) - cos^2(x) = 1 + cos(x)`?

Answer 1

`cosx=0` or `cosx = -1/2`

Explanation:

`sin^2 x - cos^2 x = 1 + cosx`
`1-cos^2 x - cos^2 x = 1 + cosx`
`-2cos^2 x - cosx = 0`
`cosx(2cosx+1)=0`
`cosx=0` or `cosx = -1/2`