How do you solve #sin^2x-7sinx=0#?
3 Answers
Explanation:
#"take out a "color(blue)"common factor of "sinx#
#rArrsinx(sinx-7)=0#
#"equate each factor to zero and solve for x"#
#sinx=0rArrx=0+kpitok inZZ#
#sinx-7=0rArrsinx=7larrcolor(blue)"no solution"#
#"since "-1<=sinx<=1#
#"the solution is therefore "x=0+kpitok inZZ#
General solution:
Explanation:
Factor:
therefore:
1:
2 can be simplified to
therefore since
So when is
the general solution is:
however if they give certain parameters such as
then for this case the answer will be:
Or, in degrees,
Explanation:
First factor the equation:
Then apply the Zero Product Rule, where if a product equals zero, then one or more of the factors must equal zero.
Solving, by isolating
There are no values of
For
In degree measure, for